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Unit 1: Atomic Structure
-see
package notes on atomic structure
Rutherford's
Nuclear Atom
A) Structure
-small, dense, positively charged nucleus containing protons (p+)
and neutrons (no)
each with a mass of 1 u (atomic mass unit)
-shells of electrons (e-) which surround thenucleus
at a great distance (and occupy
the largest part of the atom's volume); mass of 0.00054 u
NOTE: 1 u = 1.66 x 10-24 g
B) Definitions
ATOMIC NUMBER
-number of p+ in atoms nucleus
-determines the "element"
-all atoms of a particular element have the same atomic number
-elements are "atoms having the same atomic number"
MASS NUMBER
-nmber of p+ and no in an atoms nucleus
-determines the ISOTOPE
-all atoms of a particular element DO NOT have the same mass number
(#no is different)
-isotopes are "atoms with same atomic number but different mass
number"
Shorthand
method: AZ X where A =mass #, Z =atomic #,
X = element symbol
# of neutrons = mass number - atomic number
Find protons, neutrons and electrons for various examples
ATOMIC
MASS
-more correctly called the "average atomic mass" or in older cheistry
texts, the atomic weight,
this is the mass of the average atom of an element in atomic mass
units (u)
-this concept takes into account not only the mass of each individual
isotope but also their
relative abundances in nature
-since the mass of the proton and the neutron are almost equal to
1.00 u, the atomic mass
is really an average number. Calculating the atomic mass for an element
is, therefore,
calculating an average mass taking into account all of the existing
isotopes and their
percentage abundance
eg. the element consists of only two isotopes:
B-10 19.78% 10.0129 u
B-11 80.22% 11.0093 u
Calculate the atomic mass based on the above data
-average atomic mass = (%abundance of isotope 1/100 X atomic mass
of isotope 1)
+(%abundance of isotope 2/100
X atomic mass of isotope 2)
+(%abundance of isotope 3/100
X atomic mass of isotope 3)...
-average atomic mass B = (19.78/100 X 10.0129 u) + (80.22/100 X 11.0093u)
= 1.9805516 u + 8.8319011
u
= 10.81 u
eg.
Cu exists as only 2 isotopes: Cu-63 and Cu-65. If the atomic mass is 63.55,
calculate the percentage
abundance of each isotope.
Let x be the % Cu-63
Let (100 - x) be the % Cu-65
The atomic mass = [63x + 65(100 - x)]/100 = 63.55
cross multiply to get: 63x + 6500 - 65x = 63.55(100)
rearrange equation to get: 6500 - 6355 = 65x - 63x
145 = 2x
72.5 = x
The % abundance of Cu-63 is 72.5%, and % of Cu-65 = 100
- 72.5 = 27.5%
Fusion
-the formation of atomic nuclei by the joining together of the nuclei
of lighter atoms
accompanied by the release of energy;
*source of energy in the sun!
Problems
with Nuclear Reactors
Loss of Coolant
-temperature increases to the point where the metal components (fuel
rods) can melt or break
-water will turn to steam and steam can react with metals to produce
H2(g)
-pressure inside the reactor increases
-hydrogen and oxygen gas in air are explosive (breaching the building
and releasing radioactive
gases into the air)
eg. Chernobyl, Three Mile Island
-in Chernobyl, not as much coolant was used, and carbon in the form
of graphite made up the
control rods (carbon burns at high temperatures, resulting in a large
fire)
-when heat is so great the core melts, a "meltdown" is said to occur
-radioactive waste can be buried, but dispersion in the atmosphere
results in absorption into
water, plants and humans
Can a Reactor Explode like a nuclear bomb?
-no! 90% U-235 is needed to explode a nuclear bomb (this is the critical
mass), and must be
forced together under high pressure (not enough U-235 is in a reactor)
Disposal of "Spent" Fuel
-what is done with plutonium-239? (produced after decay of U-238)
-Canada buries it in sealed containers underground in the Canadian
Shield
note:
experimental results show that completely full or half full orbitals are
more stable
-jumps between s and d orbitals are allowed as they are close in Energy
-jumps between s and p orbitals do not occur as too much Energy difference